|
| |
day function in a mysql data and time field |
Day of the month can be collected from the date and time field by using the function day(). This will return day in number format and we can apply calculation to this. Note that this will not take care of month and year, for example the difference in days between 12th July 04 and 14th July 05 is two days only.
The basic query is here
SELECT day(dt2) FROM `dt_tb`
This will collect the day part from the field
For easy understanding we will create one PHP page with this query with all other fields.
The sql query is modified to display all the columns with the days and their difference for easy comparison. Here is the query used.
$query="SELECT dt,dt2,day(dt) as day1,day(dt2)as day2,(day( dt2 ) - day( dt )) as difference FROM `dt_tb`";
$qt=mysql_query($query);
echo mysql_error();
echo "<table border='1' cellspacing='1' cellpadding='0' width='400'>
<tr valign='top'>
<td><b>dt</b></td><td><b>dt2</b></td><td><b>day<br>(dt)</b></td>
<td><b>day<br>(dt2)</b></td><td><b>diffe-<br>rence</b></td></tr>";
while($nt=mysql_fetch_array($qt)){
echo "<tr valign='top'> <td><font face='Verdana' size='2' >$nt[dt]</font></td><td><font face='Verdana' size='2' >$nt[dt2]</font></td><td><font face='Verdana' size='2' >$nt[day1]</font></td><td><font face='Verdana' size='2' >$nt[day2]</font></td><td><font face='Verdana' size='2' >$nt[difference]</font></td></tr>";
}
echo "</table>";
The output of this query is here
| dt | dt2 | day
(dt) | day
(dt2) | diffe-
rence | | 2004-10-26 00:00:00 | 2005-01-25 | 26 | 25 | -1 | | 2004-05-05 23:56:25 | 2005-06-12 | 5 | 12 | 7 | | 2005-12-08 13:20:10 | 2005-06-06 | 8 | 6 | -2 |
Here is the sql code to create and fill the table with records
CREATE TABLE dt_tb (
id int(2) NOT NULL auto_increment,
dt datetime NOT NULL default '0000-00-00 00:00:00',
dt2 date NOT NULL default '0000-00-00',
PRIMARY KEY (id)
) TYPE=MyISAM;
#
# Dumping data for table `dt_tb`
#
INSERT INTO dt_tb VALUES (1, '2004-10-26 00:00:00', '2005-01-25');
INSERT INTO dt_tb VALUES (2, '2004-05-05 23:56:25', '2005-06-12');
INSERT INTO dt_tb VALUES (3, '2005-12-08 13:20:10', '2005-06-06');
| |
|
| HOME |
| SQL Tutorial List |
| SQL (Home) |
| SQL Commands |
|
|
|
|
|
| Subscribe |
|
Submit your email address and receive
article and product notifications. Your email is safe with us.
|
|
|
|
