Java ArrayList set() to replace an element inside an ArrayList based on position

ArrayList

ArrayList.set(int position , element) Update an element at given position of an ArrayList.

position : Required , Integer , Position where element is to be replaced.
element : (required ) , new element to be placed at given position.
It returns the replaced element of the ArrayList.

Note : first position inside the ArrayList is 0 ( zero ).

Examples with output add()

ArrayList<String> languages = new ArrayList<String>();
languages.add("Java");
languages.add("PHP");
languages.add("HTML");
System.out.println(languages); //[Java, PHP, HTML]
languages.set(1,"Python");
System.out.println(languages); //[Java, Python, HTML]

PHP is replaced with Python at position number 1 in above code.
We can collect the element as returned value.

ArrayList<String> languages = new ArrayList<String>();
languages.add("Java");
languages.add("PHP");
languages.add("HTML");
System.out.println(languages); //[Java, PHP, HTML]
String replaced = languages.set(0,"JQuery");
System.out.println(replaced); //Java
System.out.println(languages); //[JQuery, PHP, HTML]

If you try to replace the 4th element ( 3rd position ) then we will get error message (Index 3 out of bounds for length 3) as input position is beyond the last element of the ArrayList.

ArrayList Tutorials

add() contains() clear() clone() Java - Tutorials

ArrayList.set()

Subscribe