#include<stdio.h>
#include<conio.h>
void main ()
{
float m1,m2,m3;
float per;
float total;
//clrscr();
printf(" enter the marks of m1: ");
scanf("%f", &m1);
printf(" enter the marks of m2: ");
scanf("%f", &m2);
printf("enter the marks of m3: ");
scanf("%f", &m3);
total= m1+m2+m3;
printf("the total mark is: %.2f",total);
per = (total/300)*100;
avg = (total/3);
printf(" the percentage mark is: %.2f", per);
printf("\n the average mark is: %.2f", avg);
getch();
}
#include<stdio.h>
#include<conio.h>
void main ()
{
float m1,m2,m3;
float per,avg;
float total;
printf(" enter the marks of m1 ");
scanf("%f", &m1);
printf(" enter the marks of m2 ");
scanf("%f", &m2);
printf("enter the marks of m3 ");
scanf("%f", &m3);
total= m1+m2+m3;
printf("\n the total mark is %.2f ",total);
per = (total/300)*100;
avg = (total/3);
printf("\n the percentage mark is : %.2f ", per);
printf("\n the average mark is: %.2f", avg);
///// Grade calculation //
if(per>=80) printf("\n Grade : A");
else if(per>=60) printf("\n Grade : B");
else if(per>=40) printf("\n Grade : C");
else if(per<40) printf("\n Fail ");
getch();
}
This example demonstrates how to calculate the percentage of marks obtained by a student in five subjects.
#include <stdio.h>
int main() {
int m1, m2, m3, m4, m5;
float percentage;
printf("Enter marks for 5 subjects: ");
scanf("%d %d %d %d %d", &m1, &m2, &m3, &m4, &m5);
percentage = (m1 + m2 + m3 + m4 + m5) / 5.0;
printf("Total Percentage = %.2f%%\n", percentage);
return 0;
}
Output:
Enter marks for 5 subjects: 85 90 88 92 80
Total Percentage = 87.00%
---
This example categorizes the result into divisions based on the percentage calculated.
#include <stdio.h>
int main() {
int m1, m2, m3, m4, m5;
float percentage;
printf("Enter marks for 5 subjects: ");
scanf("%d %d %d %d %d", &m1, &m2, &m3, &m4, &m5);
percentage = (m1 + m2 + m3 + m4 + m5) / 5.0;
printf("Total Percentage = %.2f%%\n", percentage);
if (percentage >= 60) {
printf("First Division\n");
} else if (percentage >= 50) {
printf("Second Division\n");
} else if (percentage >= 40) {
printf("Third Division\n");
} else {
printf("Fail\n");
}
return 0;
}
Output:
Enter marks for 5 subjects: 70 65 60 75 80
Total Percentage = 70.00%
First Division
Tahir khan | 09-11-2018 |
i am a student. i want to become a software engineer this website is so helpful for me |