function reload3(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
var val2=form.subcat.options[form.subcat.options.selectedIndex].value;
self.location='dd3.php?cat=' + val + '&cat3=' + val2 ;
}
Using the same concept we can extend to add more dropdown list boxes.
view demo for three dropdown list here
kiran | 04-11-2013 |
i am using 3 dropdown menues, there are three table in my database,these tables are linked with foreign keys,but when i using just like your dd3.php, then 1st dropdown menu lost their value and get default value also when i getting the selected value in same page using this self.location="reg3.php?Result=" + nam; in javascript, and when i got notice error. please reply as soon as possible.. |
Aji Mohan Singh | 10-02-2014 |
keep the drop down menu value javascript after submitting |
Stacey | 15-08-2014 |
I am looking for an easy php code |
Mark | 19-11-2014 |
If I have more than 12 items in the subcategory2 table that link to one item in subcategory table, it will not list them all. Do you know why? |
smo | 19-11-2014 |
There is no reason why it should not list all 12 items ( if they are linked with category id ) |
mark | 20-11-2014 |
yeah its weird. i had to truncate the table and reenter the values then it started working. |
Mark | 20-11-2014 |
how does this solution handle duplicate values. I want it to be able to display duplicates if possible. |
smo | 20-11-2014 |
At the database table the duplicate records are to be handled. You can use distinct command to get only unique records from table and display them as options. |
Akhil Nasim | 01-04-2017 |
code is working.But i need the same code but when i select the city then i need to display the names of the person that stays in the city.how can i do this ? and also the name of the person should not displayed in dropdown , instead of i need to display just on the screen. |