any() to check elements of any iterable for True of False in Python

any(my_iterable)

my_iterable : iterable input
Return Boolean value True or False based on this table.

Difference between any() and all()

Elements of the iterable	any() Output	all() Output
All are True	True	True
All are False	False	False
One value is True ( Others False)	True	False
One value is False ( Others True)	True	False
Empty	False	True

Empty List

list=[]
print(any(list)) # False

All elements are False

list=[0,False]
print(any(list)) # False

One element is True

list=[False,True]
print(any(list))  # True

Using string

url='plus2net.com'
print(any(url))    # True
url='False'
print(any(url))    # True

We will use Dictionary

Output depends on Keys of the Dictionary ( Not Values ). If any one of the key is True then output is True. If all keys are False then output is False.

my_dict={0:'A',1:'B'}
print(any(my_dict)) # True

my_dict={0:'A',0:'B'}
print(any(my_dict)) # False

my_dict={0:True,0:False}
print(any(my_dict)) # False

my_dict={1:True,2:False}
print(any(my_dict)) # True

We will use tuple

my_tuple=(True,1,12)
print(any(my_tuple)) # True

my_tuple=(True,0)
print(any(my_tuple)) # True

my_tuple=(0,0)
print(any(my_tuple)) # False

my_tuple=(0,1)
print(any(my_tuple)) # True

Using if else

a,b,c=0,0,1
if any((a,b,c)):
  print("Yes")
else:
  print("No")

all() Iterator in and not in Membership operators
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any(): checks if at least one element in an iterable (such as a list, tuple, or set) is true

Difference between any() and all()

Empty List

All elements are False

One element is True

Using string

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