Python calendar.itermonthdays(): Month Calendar Grids

The calendar.Calendar().itermonthdays(year, month) method returns an iterator yielding day numbers for an entire calendar month. Days that fall outside the specified month (belonging to the previous or next month) are returned as 0 to pad full 7-day calendar weeks.

Parent Guide: To explore formatting full HTML tables, leap years, and weekday constants, visit the Python Calendar Module guide.

Syntax & Parameters 🔝

The itermonthdays() method is an instance method of the calendar.Calendar class:

import calendar

cal = calendar.Calendar(firstweekday=0)
day_iterator = cal.itermonthdays(year, month)
Parameter Type Required? Description
year int Yes The four-digit year (e.g. 2026).
month int Yes The month number (integer from 1 to 12).

Return Value: Returns an iterator that yields integers. Each integer represents a day of the month (1–31), or 0 if the day belongs to the preceding or succeeding month to complete a full 7-day week row.

Why Are Days Outside the Month Padded with 0? 🔝

In standard wall calendars and scheduling user interfaces, a month is displayed as a grid with 7 columns (Sunday through Saturday, or Monday through Sunday). Because months rarely start on the very first column or end cleanly on the last column, the grid needs filler cells.

itermonthdays() yields 0 for these filler positions. When rendering a web UI, Tkinter window, or console table, any day equal to 0 can be rendered as an empty cell or a muted gray date.

Basic Example: Iterating Over a Month 🔝

Let's inspect the days returned for October 2026 (a month with 31 days starting on a Thursday):

import calendar

# Default Calendar starts with Monday (firstweekday=0)
cal = calendar.Calendar()
days = list(cal.itermonthdays(2026, 10))

print("Total entries yielded:", len(days))
print("All values:", days)
Expected Output
Total entries yielded: 35
All values: [0, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 0]

Notice the three leading zeros: October 1, 2026 is a Thursday, so Monday, Tuesday, and Wednesday of that first week are represented by 0. The trailing zero pads the final week up to Sunday.

Configuring the First Day of the Week 🔝

By default, calendar.Calendar() starts weeks on Monday (0). You can configure it to start on Sunday (6) or any other weekday by passing firstweekday to the class constructor:

import calendar

# Configure Sunday as the start of the week
cal_sunday = calendar.Calendar(firstweekday=calendar.SUNDAY)
days_sun = list(cal_sunday.itermonthdays(2026, 10))

print("Sunday-first first week:", days_sun[:7])
Expected Output
Sunday-first first week: [0, 0, 0, 0, 1, 2, 3]

Chunking Days into 7-Day Calendar Rows 🔝

Because the total count of returned days is guaranteed to be a multiple of 7, you can cleanly slice the iterator into 7-day weekly rows:

import calendar

cal = calendar.Calendar(firstweekday=calendar.SUNDAY)
days = list(cal.itermonthdays(2026, 10))

# Split into 7-day chunks
weeks = [days[i:i + 7] for i in range(0, len(days), 7)]

print("Su Mo Tu We Th Fr Sa")
for week in weeks:
    print(" ".join(f"{d:2d}" if d > 0 else "  " for d in week))
Expected Output
Su Mo Tu We Th Fr Sa
             1  2  3
 4  5  6  7  8  9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31

The itermonthdays Family Comparison 🔝

Python's Calendar class provides several sibling iterator methods. Choose the one that matches your desired data structure:

Method Yielded Item Type Sample Yielded Value Padding for Outside Days
itermonthdays() int 15 0
itermonthdays2() tuple[int, int] (15, 3) (day, weekday) (0, weekday)
itermonthdays3() tuple[int, int, int] (2026, 10, 15) (year, month, day) Actual dates of outside month
itermonthdays4() tuple[int, int, int, int] (2026, 10, 15, 3) Actual dates + weekday
itermonthdates() datetime.date date(2026, 10, 15) Actual date objects of outside month

Hands-on Exercise: HTML/Table Calendar Grid Generator with Assertions 🔝

Let's construct a calendar grid generator function that takes a year and month, divides the days into 7-day rows, and returns a verified matrix structure with self-checking assertions:

Python Exercise: Month Calendar Matrix Generator
import calendar

def generate_calendar_matrix(year, month, sunday_start=True):
    start_weekday = calendar.SUNDAY if sunday_start else calendar.MONDAY
    cal = calendar.Calendar(firstweekday=start_weekday)
    
    days_list = list(cal.itermonthdays(year, month))
    # Group into 7-day week sublists
    weeks_matrix = [days_list[i:i + 7] for i in range(0, len(days_list), 7)]
    return weeks_matrix

# Test October 2026 (starts on Thursday)
oct_matrix = generate_calendar_matrix(2026, 10, sunday_start=True)

# Unit Assertions
assert len(oct_matrix) == 5  # 5 full weeks
assert len(oct_matrix[0]) == 7
assert oct_matrix[0] == [0, 0, 0, 0, 1, 2, 3]  # Thu=1, Fri=2, Sat=3
assert oct_matrix[-1][0] == 25                     # Final Sunday is 25
assert oct_matrix[-1][6] == 31                     # Final Saturday is 31

print("Generated Matrix Rows:", len(oct_matrix))
print("All calendar matrix unit assertions passed successfully!")

Practice in Google Colab & GitHub 🔝

Open in Google Colab View on GitHub

Run all itermonthdays() examples interactively, test different firstweekday configurations, and verify the calendar grid generator with unit assertions directly in Google Colab.




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