int() : to get integer object from string number or string

int('string','base') returns integer object
string: input String or number
base: (optional) base of the (input) number.

print(int('45'))  # 45

Using float data type as input

print(int(4.5))  # 4 
print(int(4.78)) # 4
print(int(4.99)) # 4
print(int(4.1))  # 4

With base

Base is 2 here

print(int('0101',2)) # 5

octal base

print(int('107',8)) # 71

Base is 16 here

print(int('ca',16)) # 202

When base is given then input must be string

print(int(123,16)) # Error

This will generate output

TypeError: int() can't convert non-string with explicit base

More examples with different base value

my_data='1011' # string input
print("With base 2 : ",int(my_data,2)) # 11
my_data='71'
print("with base 8 :",int(my_data,8)) # 57
my_data='cd' 
print("with base 16 :",int(my_data,16)) # 205

Output

With base 2 :  11
with base 8 : 57
with base 16 : 205

None type to int

This will generate error as we can't convert None type variable to Integer.

a=None
b=int(a) #TypeError: int() argument must be a string, a bytes-like object or a real number, not 'NoneType'
print(b)

Solution , use like this and assign 0 if it is None

a=None
b=int(a or 0) 
print(b) # 0

All Built in Functions in Python bin() complex()

Math Functions math.fabs() Python- Tutorials

Subhendu Mohapatra

Author

🎥 Join me live on YouTube

Passionate about coding and teaching, I publish practical tutorials on PHP, Python, JavaScript, SQL, and web development. My goal is to make learning simple, engaging, and project‑oriented with real examples and source code.

Subscribe to our YouTube Channel here