index() method to get position of first matching element in a list

All list methods

index(x,[start[,end]])

x : input data to check
start: Optional, starting of the search position
end: Optional, End of search position

returns number of matching position.

my_list=['a','b','c','b','a','d']
print("Position of first matching  a : ", my_list.index('a'))
print("Position of first matching  b : ", my_list.index('b'))
print("Position of first matching  d : ", my_list.index('d'))

Output

Position of first matching  a :  0
Position of first matching  b :  1
Position of first matching  d :  5

Using start and end positions

my_list=['a','b','c','b','a','d','a']
print("Position of first matching  a : ", my_list.index('a',2))
print("Position of first matching  b : ", my_list.index('b',1,4))
print("Position of first matching  a : ", my_list.index('a',5))

Output

Position of first matching  a :  4
Position of first matching  b :  1
Position of first matching  a :  6

If not found then ValueError will be raised.

my_list=['a','b','c','b','a','d','a']
print("Position of first matching  b : ", my_list.index('b',5))

This code will give error as b is not available after position 5. Note that first position is 0^th in the list.
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index() to get matching position in list

Using start and end positions

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