log10(x) returns log of input number x with base 10
import math
print(math.log10(2))  # 0.3010299956639812
print(math.log10(4))  # 0.6020599913279624
print(math.log10(5))  # 0.6989700043360189
Using negative number
For any value less than or equal to 0 , we will get ValueError
import math
Above code will generate error.

log2 log1p() log()

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