# Numpy zeros()

Numpy

``numpy.zeros(shape, dtype=None, order='C')``
Return array filled with zeors of given shape and type.
 `shape` Int, or sequence ( 2,3), shape of the output array `dtype` data-type( Optional ), Data Type of returned array. `order` {'C','F'} Optional, how the output is to be stored. C- style or Fortan style
 Shape: (3, 4) Dimension 2 Shape: (4, 3) Dimension 2

## Using shape

``````import numpy as np
ar=np.zeros(4)
print(ar) # [0. 0. 0. 0.]``````
Let us use different value for shape
``````ar=np.zeros((4,2))
print(ar)``````
Output
``````[[0. 0.]
[0. 0.]
[0. 0.]
[0. 0.]]``````
``ar=np.zeros((4,1))``
Output
``````[[0.]
[0.]
[0.]
[0.]]``````

## dtype

We will try to return string dtype
``````import numpy as np
ar=np.zeros(4,dtype=str)
print(ar) # ['' '' '' '']``````
Output
``['' '' '' '']``
dtype=float
``ar=np.zeros(4,dtype=float)``
Output
``[0. 0. 0. 0.]``
dtype=int
``my=np.zeros(4,dtype=int)``
Output
``[0 0 0 0]``
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