Numpy zeros() to get array filled with zeros

numpy.zeros(shape, dtype=None, order='C')

Return array filled with zeors of given shape and type.

`shape`	Int, or sequence ( 2,3), shape of the output array
`dtype`	data-type( Optional ), Data Type of returned array.
`order`	{'C','F'} Optional, how the output is to be stored. C- style or Fortan style


Shape: (3, 4) Dimension 2	Shape: (4, 3) Dimension 2

Using shape

import numpy as np
ar=np.zeros(4)
print(ar) # [0. 0. 0. 0.]

Let us use different value for shape

ar=np.zeros((4,2))
print(ar)

Output

[[0. 0.]
 [0. 0.]
 [0. 0.]
 [0. 0.]]

ar=np.zeros((4,1))

Output

[[0.]
 [0.]
 [0.]
 [0.]]

dtype

We will try to return string dtype

import numpy as np
ar=np.zeros(4,dtype=str)
print(ar) # ['' '' '' '']

Output

['' '' '' '']

dtype=float

ar=np.zeros(4,dtype=float)

Output

[0. 0. 0. 0.]

dtype=int

my=np.zeros(4,dtype=int)

Output

[0 0 0 0]

Numpy eye() bincount() arange() linspace() Advanced Array creation

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