oct() to convert integer to Octal number string in python

oct(number)

number :input integer number
Return the Octal number as string.

Examples

my_num=27
print(oct(my_num))  # 0o33

This will generate TypeError

num=27.45
print(oct(num))

TypeError: 'float' object cannot be interpreted as an integer

print(oct(0b11011)) # 0o33

In above code the input binary number is equivalent to integer 27.

You can use bin() to get the binary output

print("Binary Number : ", bin(27)) # Binary Number :  0b11011

print(oct(0x1b)) # 0o33

In above code the input Hex number is equivalent to integer 27 You can use hex() to get the Hex output

print("Hex  Number : ", hex(27)) # Hex  Number :  0x1b

In our octal output, 0o is always prefixed. As the output is a string we can remove it like this

my_oct=oct(27)
print(my_oct[2:]) # 33

Without using oct() and by using format()

my_num=27
print(format(my_num,'o')) # 33