Sample Codes using Python Date functions

Display today's,yesterday, & tomorrow

from  datetime import date,timedelta
print("Today date : ",date.today()) # Today date :  2021-12-23
print("Today Month: ",date.today().month) # Today Month: 12
print("Yesterday : ",date.today() - timedelta(days=1)) # Yesterday : 2021-12-22
print("Tomorrow : ",date.today() + timedelta(days=1))  # Tomorrow : 2021-12-24

Display next five days date

from datetime import date,timedelta
for i in range(5):
    print(" Date : ",date.today() + timedelta(days=i))

 Date :  2021-12-29
 Date :  2021-12-30
 Date :  2021-12-31
 Date :  2022-01-01
 Date :  2022-01-02

Check if current year is a leap year

from  datetime import date
year=date.today().year
#year=2020
if(year%4==0):
    print("This is a leap year : ",year)
else:
    print("This year is not a leap year : ", year)

List all Saturday & Sundays of a Period

from datetime import datetime,timedelta
#start_date='1 Dec 2021' # date as string 
#end_date='31 DEc 2021'
start_date=input("Enter start date: ")
end_date=input("Enter End date:")
start_date=datetime.strptime(start_date,'%d %b %Y') # match the format
end_date=datetime.strptime(end_date,'%d %b %Y')
day_count = (end_date - start_date).days + 1 # gap in Number of days

for dt in (start_date + timedelta(n) for n in range(day_count)):
    if(dt.isoweekday()==7 or dt.isoweekday()==6 ): # Saturday & Sunday
        print(dt.strftime('%Y-%m-%d (%A)'))

Enter start date: 1 Dec 2021
Enter End date:25 Dec 2021
2021-12-04 (Saturday)
2021-12-05 (Sunday)
2021-12-11 (Saturday)
2021-12-12 (Sunday)
2021-12-18 (Saturday)
2021-12-19 (Sunday)
2021-12-25 (Saturday)

Weekday from input date

from  datetime import datetime
my_date1=input("Enter  date dd/mm/YYYY: ")
my_date=datetime.strptime(my_date1,'%d/%m/%Y') # match the format
print(my_date1 ,my_date.strftime('%A'))

Enter  date dd/mm/YYYY: 31/12/2022
31/12/2022 Saturday

Display the date for the first Monday of current month

from  datetime import date
year=date.today().year   # change this to use year as input
month=date.today().month # change this to use month as input
#month=1
dt=date(year,month,1)    # first day of month
first_w=dt.isoweekday()  # weekday of 1st day of the month
if(first_w==1): # if it is Monday 
	monday1=first_w
else:
    monday1=9-first_w    
dt=date(year,month,monday1)
print(dt.day,dt.month,dt.year)

Adding Time

import datetime
tm = datetime.datetime.now() + datetime.timedelta(minutes=35,hours=2)
print(tm.strftime('%H:%M:%S')) # 13:33:37

Findout first day of next month

from  datetime import date,timedelta
import datetime
#dt=date.today() #  todays date 
dt=datetime.datetime(2019,12,1) # YYYY,mm,dd    format any valid date
dt2=datetime.datetime(dt.year + dt.month // 12,dt.month % 12 + 1, 1)
print("First day of next month :", dt2 )

Last day of current month

dt2=datetime.datetime(dt.year + dt.month // 12,dt.month % 12 + 1, 1)-timedelta(days=1)
print("Last day of current month : " , dt2 )