Sum of all digits of an input number in Python

Example 1

We read the input as string ( by default ) and as string is an iterable object we can find the each digit ( char as a string ) by using the position starting from 0 as first position.

In next step covert each char to integer by int() function and then add them all to get the sum of the digits.

my_sum of the digits of an input number in Python by using floor , reminder & by using string position

n=input("Enter a Number :")
my_sum=0
for i in range(0,len(n)):
    my_sum=my_sum+int(n[i])
print("Sum of digits in number : ", my_sum)

Output

Enter a Number :549
sum of digits in number :  18

In above code we used len() to get the number of elements ( or char here ) in the string object n.

Example 2

To any number if we divide by 10 then reminder will be the right most digit.
If 4534 is divided by 10 then reminder is 4 ( the right most digit ).
The floor ( or quotient ) value of 4534 after the division by 10 will be 453, so we can loop through and find the floor values till the floor value became 0. Inside the loop we can get reminders as digits of the number. Here is the code.

n=int(input("Enter a Number :"))
my_sum=0
while(n>0):
    i=n%10   # reminder value of division
    my_sum=my_sum+i
    n=n//10  # floor value of division
print("sum of digits in number=",my_sum)

Output

Enter a Number :1251
sum of digits in number=9

Using recursive function

n=int(input("Enter a Number :"))
total=0
def my_sum(n):
    global total
    if n<=0:
        return 0
    else:
        i=n%10   # reminder value of division
        total=total+i
        n=n//10  # floor value of division
        my_sum(n) # Using recursive function 
        return total
print("sum of digits in number = ",my_sum(n))

We are using recursive function here.
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Subhendu Mohapatra

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Sum of digits of an input number in Python

Example 1

Example 2

Using recursive function

Subhendu Mohapatra