intersection() method in Python set

All set methods

Returns a new set with common elements only. Original set remains unchanged.
  • Video Tutorial on Set


intersection using & operator

All Common elements in sets
Using ampersand ( & ) operator
A={1,2,3}
B={3,4,5}
print(A & B)
Output ( Note 3 is the only common element )
{3}

Using type()

We can check the output by using type()
A={1,2,3}
B={3,4,5}
x=A & B 
print(type(x))
Output
<class 'set'>

Using intersection() method

A={'a','b','c'}
B={'a','y','z'}
print(A.intersection(B))
Output
{'a'}

Using more than one sets

We can use any number of sets with intersection()
A={'a','b','c'}
B={'a','y','z'}
C={'a','k','l'}
print(A & B & C)
Output
{'a'}

intersection() method

Using string ( iterable object ) with intersection() method
A={'a','b','c','x','y'}
B='Alex'
print(A.intersection(B))
Output
{'x'}
Using list with intersection() method.
A={'a','b','c'}
B=['a','x','y']
print(A.intersection(B))
Output
{'a'}
Below code will generate error.
print(A & B)
 TypeError: unsupported operand type(s) for &: 'set' and 'list'

intersection_update()

In all above code by using intersection() we created a new set. By using intersection_update() method we can change the original set with common elements.
All set methods Questions with solutions on set
union() difference() symmetric_difference()

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