isdisjoint() method checks and returns True or False based on common element among them

isdisjoint() method for set

All set methods

isdisjoint(set) takes one set ( any iterable ) as argument .

set : set to checked
While checking we can use iterable objects like string , list etc Returns : True or False
isdisjoint False

A={'x','y','z'}
B={'x','b','c'}
print(A.isdisjoint(B))

Output ( 'x' is the common element among two sets A and B )

False

A={'x','y','z'}
B={'a','b','c'}
print(A.isdisjoint(B))

Output ( There is no common element among two sets A and B )

True

Using stirng

String is an iterable objects

A={'x','y','z'}
B='Alex'
print(A.isdisjoint(B))

Outut ( here x is the common element )

False

Using list

List is an iterable objects

A={'x','y','z'}
B=['a','b','c']
print(A.isdisjoint(B))

Output (No common elements )

True

All set methods Questions with solutions on set issubset() issuperset()

tuple set Dictionary Python- Tutorials

This article is written by plus2net.com team.

plus2net.com

isdisjoint() method for set

Using stirng

Using list

Subscribe