issuperset(set) takes one set ( any iterable ) as argument .
set
: set to checked
While checking we can use iterable objects like string , list etc
Returns : True or False
A={'x','y','z','a','b','c'}
B={'x','y','z'}
print(A.issuperset(B))
Output ( All elements of B is present in inside A )
True
A={'x','y','z','a','b','c'}
B={'x','y','z','k','l','m'}
print(B.issubset(A))
Output ( There are elements in B which are not in A )
False
Using stirng
String is an iterable objects
A={'y','t','W','o','e'}
B='We'
print(A.issuperset(B))
Outut ( here all elements of B is present in A )
True
Using list
List is an iterable objects
A={'x','y','a','b'}
B=['a','b']
print(A.issuperset(B))
Output ( all elements of B is present inside A )
True
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isdisjoint()
issubset()
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