issuperset() method checks and returns True or False based on common element among them

issuperset() method for set

All set methods

issuperset(set) takes one set ( any iterable ) as argument .

set : set to checked
While checking we can use iterable objects like string , list etc Returns : True or False
issubset True

A={'x','y','z','a','b','c'}
B={'x','y','z'}
print(A.issuperset(B))

Output ( All elements of B is present in inside A )

True

A={'x','y','z','a','b','c'}
B={'x','y','z','k','l','m'}
print(B.issubset(A))

Output ( There are elements in B which are not in A )

False

Using stirng

String is an iterable objects

A={'y','t','W','o','e'}
B='We'
print(A.issuperset(B))

Outut ( here all elements of B is present in A )

True

Using list

List is an iterable objects

A={'x','y','a','b'}
B=['a','b']
print(A.issuperset(B))

Output ( all elements of B is present inside A )

True

All set methods Questions with solutions on set isdisjoint() issubset()

tuple set Dictionary Python- Tutorials

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