sorted() to create a new sorted list by using an iterable in Python

sorted(object,reverse,key) Returns sorted list of input iterable object

`object`	iterable Object to be sorted .
`reverse`	(Optional ) if set to True then reverse or descending order is used.
`key`	(Optional ) default is None, Function used for sorting each element.

Original iterable object is not chagned.
Using a numeric list

my_list=[12,3,8,7,14]
print(sorted(my_list))
#print(my_list)

Output

[3, 7, 8, 12, 14]

You can check the original list also ( unchanged ) .

Using a list of string

my_list=['Orange','Banana','Apple','Mango']
print(sorted(my_list))

Output

['Apple', 'Banana', 'Mango', 'Orange']

Using a string

my_str='plus2net'
print(sorted(my_str))

Output

['2', 'e', 'l', 'n', 'p', 's', 't', 'u']

reverse=True ( Optional )

We will change the order of sorting by adding reverse=True

my_list=['Orange','Banana','Apple','Mango']
print(sorted(my_list,reverse=True))

Output

['Orange', 'Mango', 'Banana', 'Apple']

Using numbers

my_list=[12,3,8,7,14]
print(sorted(my_list,reverse=True))

Output

[14, 12, 8, 7, 3]

Using key ( Optional )

We can add key to use customized sorting function.
Let us arrange in the order of length of the elements ( we will use len function )

my_list=['Three','One','Seven','thirtyfive','Two']
print(sorted(my_list,key=len))

Output ( in the order of increasing length of element )

['One', 'Two', 'Three', 'Seven', 'thirtyfive']

We can add reverse=True to get in descending order

print(sorted(my_list,key=len,reverse=True))

Output

['thirtyfive', 'Three', 'Seven', 'One', 'Two']

We can use user defined function to get sorting order based on the 2^nd element of tuple.

my_list=[(3,5),(2,1),(8,4),(3,7)]
def my_sort(my_data):
    return my_data[1]
print(sorted(my_list,key=my_sort))

Output ( in the increasing order of each 2^nd element )

[(2, 1), (8, 4), (3, 5), (3, 7)]

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Subhendu Mohapatra

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