sqrt(x) returns squqre root of input number
import math
print(math.sqrt(4))    # 2.0 
print(math.sqrt(16))   # 4.0 
print(math.sqrt(20))   # 4.47213595499958
print(math.sqrt(0))    # 0.0
Using negative number
For any value less than 0 , we will get ValueError
import math
Above code will generate error.

log10 modf()


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