sqrt() math function to get square root of positive integer in Python

sqrt()

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sqrt(x) returns squqre root of input number as float data type.

import math
print(math.sqrt(4))    # 2.0 
print(math.sqrt(16))   # 4.0 
print(math.sqrt(20))   # 4.47213595499958
print(math.sqrt(0))    # 0.0

Using negative number
For any value less than 0 , we will get ValueError

import math
print(math.sqrt(-15))

Above code will generate error.

Output of math.sqrt() is float data type. We can use type() to get the data type.

import math
x=math.sqrt(25)
print(x)        # 5.0
print(type(x))  # <class 'float'>

We can use int() to convert output to integer data type.

import math
x=math.sqrt(25)
y=int(x)
print(type(y))  # <class 'int'>

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plus2net.com

	04-07-2020
Why the square root of 16 is 4.0 and why not 4???

	05-07-2020
The output of sqrt is float always. Added the part to convert float data type to integer.