columns() to get column header names from DataFrame in Pandas

Pandas DataFrame column listing and adding new columns using insert, dropping columns and renaming

We can create one DataFrame by using dictionary or by reading any Excel or reading CSV file. We will display the column names of this dataframe here.

By using columns

import pandas as pd 
my_dict={'NAME':['Ravi','Raju','Alex','Ron','King','Jack'],
         'ID':[1,2,3,4,5,6],
         'MATH':[80,40,70,70,60,30],
         'ENGLISH':[80,70,40,50,60,30]}
df = pd.DataFrame(data=my_dict)
print(df.columns) # Object

Output

Index(['NAME', 'ID', 'MATH', 'ENGLISH'], dtype='object')

Getting any perticular column

print(df.columns[2]) # Math

By using keys()

print(df.keys())

Output

Index(['NAME', 'ID', 'MATH', 'ENGLISH'], dtype='object')

By using for loop

for cols in df.columns:
  print(cols)

Output

NAME
ID
MATH
ENGLISH

To get data from each column of DataFrame

for cols in df.columns:
  print(df[cols])

Calling a function by passing each column as parameter and display data.

def my_fun(cols): # function to receive column name as parameter 
    print(df[cols])
for cols in df.columns:
    my_fun(cols)

By using list

print(list(df.columns))

Output

['NAME', 'ID', 'MATH', 'ENGLISH']

By using tolist()

print(df.columns.values.tolist())

Output

['NAME', 'ID', 'MATH', 'ENGLISH']

Create empty DataFrame with only column names

df = pd.DataFrame(columns=['A','B','C','D','E','F','G'])

Data type of columns

Here dt_start column is string object, we can convert the string data type to date and time by using to_datetime() function. Check the difference in output after converting the column data type.

import pandas as pd 
my_dict={'NAME':['Ravi','Raju','Alex'],
         'dt_start':['1-1-2020','2-1-2020','5-1-2020']
         }
df = pd.DataFrame(data=my_dict)
#df['dt_start'] = pd.to_datetime(df['dt_start']) # converts to datetime data
print(df.dtypes)

Adding column

Using a list.
Take care that number of elements should match with existing data. Otherwise we will get value error
ValueError: Length of values (5) does not match length of index (6)

l1=['Four','Three','Five','Six','Two','Three']
df['my_class']=l1

Above code will add the column at the end of the DataFrame. We can use insert()

l1=['Four','Three','Five','Six','Two','Three']
df.insert(2,'my_class',l1,True)
print(df.columns.values.tolist())

Output

['NAME', 'ID', 'my_class', 'MATH', 'ENGLISH']

Here also we have to match the existing length of data. The Boolean options at the end is to allow duplicate or not, default value is False.

We can use assign() to add a new column but here the original DataFrame remain same ( no change ). Column is also added at the end.

l1=['Four','Three','Five','Six','Two','Three']
df2=df.assign(my_class=l1)
print(df2.columns.values.tolist())

We can use a dictionary with keys ( unique ) and value from any existing column.

d1={'Four':'Ravi','Three':'Raju','Five':'Alex','Six':'Ron',
	'Two':'King','Eight':'Jack'}
df['my_class']=d1
print(df.columns.values.tolist())

We can use single value for all the rows of the new column. We will use all above methods.

We are adding my_class column with single value 'Four' for all rows

df['my_class']='Four' # adding column at the end 
df.insert(2,'my_class','Four') # at 2nd position 
df2=df.assign(my_class='Four') # new DataFrame with added column

How to add column with increasing value?

df = df.reset_index() 
df = df.rename(columns={"index":"New_ID"})
df['New_ID'] = df.index + 1000  # starting from 1000

Here reset_index() adds old index as a column, and a new sequential index is used.

Delete a column

using drop

df.drop(labels='Page Value',axis=1,inplace=True)

Changing column names

Assigning new names, maintain sequency.

df.columns = ['Page','p_view','u_view','avg']

Updating single column name

df = df.rename(columns={"my_class":"my_class4"})

Pandas DataFrame describe() head() rename()

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columns(): List of Column names of DataFrame

By using columns

Create empty DataFrame with only column names

Data type of columns

Adding column

Delete a column

Changing column names

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